2022 Waec Gce mathematics question and answers: Most likely Weac Mathematics answer 2022 to Objectives Essay question is available here. Candidates that applied for the West African Examination Council (Waec Gce) SSCE Examination will write their Waec Gce mathematics paper on Monday 20th September 2022.

The Weac mathematics question and answer 2022 for preparation towards Waec Gce start exam paper 2 & 1: Essay & Objective which will commence from 9:30 am – 12:00 pm and end by 3:00 pm – 4:30 pm.

In this post, we will be posting samples of the Waec Gce mathematics questions for candidates that will participate in the examination.

Note that below is the questions from Waec Gce mathematics past questions and answers that we feel are likely questions for preparation.

### 2022 Waec Gce Mathematics Question and Answers ( Most likely Questions to Expect)

**1. Which of these numbers is not less than -2?**

- -1,
- -3,
- -4,
- -5.
- -6

**Solution Solving:** -2 is greater than -2, -3, -4, -5, -6 and so on. But -1 is greater than -2.

**The Correct Answer is A): **Because it is greater than -2.

**2. -6 is greater than -2 but less than -7? True or false**

- True
- Both
- False
- None of the above

**Solving for the solution: **-6 is greater than any number from -7 to the negative infinity but less than any number from -5 to the positive infinity.

**The Correct Answer is C): **Because -6 is not greater than -2 and it is not less than -7.

**3. Add 26b + 12a + 16a – 4b**

- 22b + 28a
- -22b + 28a
- 22b – 28a
- -22b – 28a

**Solution Solving for Questions 3:** Firstly, you have to Collect like terms. Therefore, we have;

- 26b – 4b + 12a + 16a.
- Next, we have 26b – 4b = 22b
- And 12a + 16a = 28a
- Therefore, we have 22b + 28a

**The Correct Answer is A): **22b + 28a

**4. Multiply this equation: (x – 6)(2x + 7)?**

- 2×2 + 5x – 42
- 2×2 – 5x – 42
- 2×2 – 5x + 42
- 2×2 + 5x + 42
- -2×2 + 5x – 42

**Solving for question 4 solution: **Here, we start by removing the bracket

Thus; 2×2 + 7x – 12x – 42

Hence, 2×2 – 5x – 42

**The Correct Answer is B): **2×2 – 5x – 42

**5. Factorise the following: 5×2 – 15x – 20?**

- 5(x+4)(x+1).
- -2(x-4)(x+5)
- -5(x+4)(x-1)
- 5(x-4)(x+1)

Solution Solving to question 5: First find the **lcm** of 5, 15 and 20 = 5(x2 – 3x – 4).

- = 5(x2 – 4x + x – 4).
- = 5{x(x – 4) +1(x – 4)}.
- = 5(x-4)(x+1).

**The Correct Answer is D):** 5(x-4)(x+1)

A.75 B. 80 C. 55 D. 125.

A. 2 B. -2 C. ½ D. -1/2

A. N1,000 B. N2,500 C. 2,000 D. N10,000

A. 8 B. 16 C. 10 D. 14

A. 2cos2Ө B. 2sin2Ө C. -2cos2Ө D. -2sin2Ө

A. 11 B. -11 C. 8 D. -8

A. x3 – 7x + 6

B. x3 + 7x – 6

C. x3 – 7x – 6

D. x3 + 7x + 6

A. x < 7/4

B. x > 7/4

C. 7x < 4

D. -4x < 7

A. 13 B.20 C. 12 D. 21

A. 1056

B. 3016

C. 1036

D. 5016

A. 1 B. -1 C. 19 D. -19

### Waec Gce General Mathematics Theory and Answer Paper 2, WASSCE

- Copy and complete the table of values for the equation y = 2×2 – 7x – 9 for -3 ≤ x ≤ 6.

X |
-3 | – 2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |

Y |
13 | -9 | -14 | -12 | 6 |

- Using scales of 2 cm to 1 unit on the x-axis and 2 cm to 4 units on the y – axis, draw the graph of y = 2×2 – 7x – 9 for -3 ≤ x ≤ 6.
- Use the graph to estimate the:
- roots of the equation 2×2 – 7x = 26;

(ii) coordinates of the minimum point of y;

(iii) range of values for which 2×2 – 7x < 9.

**A solution to Question 1**

The Chief Examiner reported that the majority of the Candidates’ who attempted this question got right the complete table of values for which y = 2×2 – 7x – 9. However, many failed to plot the points on the graph correctly on the graph thereby losing marks. Also, they could not read up values from the graph to answer subsequent questions.

In part (a), the Candidates were expected to complete the table as follows:

X |
-3 | – 2 | -1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 |

Y |
30 | 13 | 0 | -9 | -14 | -15 | -12 | -5 | 6 | 21 |

In part (c), from the graph, the roots of the equation 2×2 – 7x = 26 were obtained by drawing a line through y = 17 to meet the curve y = 2×2 – 7x – 9. The required roots are – 2.2 ± 0.1 and 5.8 ± 0.1. The coordinates of the minimum point of y is 1.8 ± 0.1, -15 ± 0.4. The ranges -10.1<x<4.5

**Question 2**

Marks | 1 | 2 | 3 | 4 | 5 |

Number of students | m + 2 |
m – 1 |
2m – 3 |
m + 5 |
3m – 4 |

The table shows the distribution of marks scored by some students in a test.

- If the mean mark is, find the value of
*m*. - Find the:

(i) inter-quartile range;

(ii) probability of selecting a student who scored at least 4 marks in the test.

**The solution to Question 2**

x |
1 | 2 | 3 | 4 | 5 | Total |

f |
m+2 |
m-1 |
2m-3 |
m+5 |
3m-4 |
8m-1 |

fx |
m+2 |
2m-2 |
6m-9 |
4m+20 |
15m-20 |
28m-9 |

From the table,and, so thatand solving yields *m* = 3.

In part (b) (i), since *m* has been gotten to be 3, the table then becomes:

x |
1 | 2 | 3 | 4 | 5 |

f |
5 | 2 | 3 | 8 | 5 |

Cf | 5 | 7 | 10 | 18 | 23 |

Therefore, interquartile range = 4 – 2 = 2.

Finally, in part (b) (ii), the probability of selecting a student who scored **at least** 4 marks iswhereas most Candidates’ made use of **at most** 4 marks to obtain

**NOTE THAT**:

All the questions drop down are not exactly 2022 Waec Gce Mathematics questions and answers but likely Waec Gce Mathematics repeated questions and answers, so if you can practice the questions it can also be of help.

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